Imagine that you are throwing a baseball off a cliff, but doing so straight up (while standing at the edge of the cliff). The ball will go straight up and come straight back down alongside the cliff, landing at at the base of the cliff 30 m below. The initial upward velocity of the baseball is 25 m/s.
a. How long will it take the baseball to reach its maximum height?
b. How high up will it travel?
c. How long would it take to come right back to your hand (where it left)?
d. How long (in total) would it take to leave your hand, go up and travel to the very bottom of the cliff? There is a long way to solve this problem, but also a shorter (one equation) way: Note that the shorter method will require the use of the quadratic formula. If you don't like using the quadratic formula, you can find a solver online:
http://www.math.com/students/calculators/source/quadratic.htm
e. Finally, what is the approximate shape of the graphs of d vs. t and v vs. t?
No comments:
Post a Comment